WBR234: Difference between revisions
Jump to navigation
Jump to search
Rim Halaby (talk | contribs) No edit summary |
m refreshing WBR questions |
||
(6 intermediate revisions by 3 users not shown) | |||
Line 1: | Line 1: | ||
{{WBRQuestion | {{WBRQuestion | ||
|QuestionAuthor={{Rim}} | |QuestionAuthor= {{Rim}} (Reviewed by Will Gibson) | ||
|ExamType=USMLE Step 1 | |ExamType=USMLE Step 1 | ||
|MainCategory=Physiology | |MainCategory=Physiology | ||
Line 8: | Line 8: | ||
|MainCategory=Physiology | |MainCategory=Physiology | ||
|SubCategory=Renal | |SubCategory=Renal | ||
|MainCategory=Physiology | |||
|MainCategory=Physiology | |MainCategory=Physiology | ||
|MainCategory=Physiology | |MainCategory=Physiology | ||
Line 22: | Line 23: | ||
|Prompt=An experiment to measure the filtration fraction in healthy volunteers is conducted. One sample of the available urine and serum values is shown below. If the urine flow is 2.0 ml/min, what is the best approximate filtration fraction? | |Prompt=An experiment to measure the filtration fraction in healthy volunteers is conducted. One sample of the available urine and serum values is shown below. If the urine flow is 2.0 ml/min, what is the best approximate filtration fraction? | ||
[[Image | [[Image:Screen Shot 2013-09-08 at 9.43.33 PM.png|600px]] | ||
|Explanation=Despite the presence of several parameters, utilization of only creatinine and PAH is required to calculate the filtration fraction. | |Explanation=Despite the presence of several parameters, utilization of only [[creatinine]] and [[PAH]] is required to calculate the filtration fraction. | ||
Filtration fraction (FF) is calculated by the following equation: FF (%) = (GFR / RPF) x 100 | Filtration fraction (FF) is calculated by the following equation: FF (%) = (GFR / RPF) x 100 | ||
GFR = (UCr x V)/PCr = (100 x 2)/1 = 200 | GFR = (UCr x V)/PCr = (100 mg/dL x 2 ml/min ) / (1 mg/dL) = 200 mL/min | ||
RPF = (UPAH x V)/PPAH = (50 x 2)/0.2 = 500 | RPF = (UPAH x V)/PPAH = (50 mg/dL x 2 ml/min ) / (0.2 mg/dL) = 500 mL/min | ||
FF (%) = (GFR / RPF) x 100 = (200/500) x 100 = 0.4 x 100 = 40% | FF (%) = (GFR / RPF) x 100 = (200/500) x 100 = 0.4 x 100 = 40% | ||
Abbreviations:<br> | |||
* GFR: Glomerular Filtration Rate (mL/min) | |||
* UCr: Urinary creatinine concentration (mg/mL) | |||
|AnswerA=20 | * V: Volume of urine produced per unit time (mL/min) | ||
|AnswerAExp= | * PCr: Plasma creatinine concentration (mg/mL) | ||
* RPF: Renal plasma flow | |||
* UPAH: Urinary Para-aminohippurate (PAH) concentration (mg/mL) | |||
* PPAH: Plasma Para-aminohippurate (PAH) concentration (mg/mL) | |||
* FF: Filtration fraction | |||
|AnswerA=20% | |||
|AnswerAExp=One could obtain this number by using the ratio of the serum PAH to serum creatinine. However, this does not reflect any standard physiologic parameter. | |||
|AnswerB=30% | |AnswerB=30% | ||
|AnswerBExp=According to the calculation, this is an incorrect answer. | |AnswerBExp=According to the calculation, this is an incorrect answer. | ||
Line 41: | Line 48: | ||
|AnswerD=40% | |AnswerD=40% | ||
|AnswerDExp=According to the calculation, this is a correct answer. | |AnswerDExp=According to the calculation, this is a correct answer. | ||
|AnswerE= | |AnswerE=100% | ||
|AnswerEExp= | |AnswerEExp=This number could be achieved by dividing the renal creatinine concentration by the serum creatinine concentration. However, this measure does not reflect any normal physiologic parameter. | ||
|EducationalObjectives=The filtration fraction can be calculated by the following formula: FF (%) = (GFR/RPF) x 100 | |||
|References=First Aid 2015 page 530 | |||
|RightAnswer=D | |RightAnswer=D | ||
|Approved= | |WBRKeyword=Renal physiology, Renal plasma flow, Filtration fraction, Nephrology, Kidney, GFR, PAH, Creatinine, | ||
|Approved=Yes | |||
}} | }} |
Latest revision as of 02:49, 28 October 2020
Author | [[PageAuthor::Rim Halaby, M.D. [1] (Reviewed by Will Gibson)]] |
---|---|
Exam Type | ExamType::USMLE Step 1 |
Main Category | MainCategory::Physiology |
Sub Category | SubCategory::Renal |
Prompt | [[Prompt::An experiment to measure the filtration fraction in healthy volunteers is conducted. One sample of the available urine and serum values is shown below. If the urine flow is 2.0 ml/min, what is the best approximate filtration fraction? |
Answer A | AnswerA::20% |
Answer A Explanation | AnswerAExp::One could obtain this number by using the ratio of the serum PAH to serum creatinine. However, this does not reflect any standard physiologic parameter. |
Answer B | AnswerB::30% |
Answer B Explanation | AnswerBExp::According to the calculation, this is an incorrect answer. |
Answer C | AnswerC::35% |
Answer C Explanation | AnswerCExp::According to the calculation, this is an incorrect answer. |
Answer D | AnswerD::40% |
Answer D Explanation | AnswerDExp::According to the calculation, this is a correct answer. |
Answer E | AnswerE::100% |
Answer E Explanation | AnswerEExp::This number could be achieved by dividing the renal creatinine concentration by the serum creatinine concentration. However, this measure does not reflect any normal physiologic parameter. |
Right Answer | RightAnswer::D |
Explanation | [[Explanation::Despite the presence of several parameters, utilization of only creatinine and PAH is required to calculate the filtration fraction.
Filtration fraction (FF) is calculated by the following equation: FF (%) = (GFR / RPF) x 100 GFR = (UCr x V)/PCr = (100 mg/dL x 2 ml/min ) / (1 mg/dL) = 200 mL/min RPF = (UPAH x V)/PPAH = (50 mg/dL x 2 ml/min ) / (0.2 mg/dL) = 500 mL/min FF (%) = (GFR / RPF) x 100 = (200/500) x 100 = 0.4 x 100 = 40% Abbreviations:
Educational Objective: The filtration fraction can be calculated by the following formula: FF (%) = (GFR/RPF) x 100 |
Approved | Approved::Yes |
Keyword | WBRKeyword::Renal physiology, WBRKeyword::Renal plasma flow, WBRKeyword::Filtration fraction, WBRKeyword::Nephrology, WBRKeyword::Kidney, WBRKeyword::GFR, WBRKeyword::PAH, WBRKeyword::Creatinine |
Linked Question | Linked:: |
Order in Linked Questions | LinkedOrder:: |