WBR0990: Difference between revisions
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|MainCategory=Physiology | |MainCategory=Physiology | ||
|SubCategory=Pulmonology | |SubCategory=Pulmonology | ||
|MainCategory=Physiology | |||
|MainCategory=Physiology | |MainCategory=Physiology | ||
|MainCategory=Physiology | |MainCategory=Physiology | ||
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'''Educational objective:''' | '''Educational objective:''' | ||
'''References:''' | '''References:''' | ||
|AnswerA=0.72 mmHg·min/L | |AnswerA=0.72 mmHg·min/L | ||
|AnswerAExp=Incorrect: See calculation in the explanation | |AnswerAExp=Incorrect: See calculation in the explanation | ||
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|AnswerE=20.83 mmHg·min/L | |AnswerE=20.83 mmHg·min/L | ||
|AnswerEExp=Incorrect: See calculation in the explanation | |AnswerEExp=Incorrect: See calculation in the explanation | ||
|EducationalObjectives=Pulmonary vascular resistance is given by the change in pressure across the pulmonary vasculature divided by the cardiac output. | |||
|References=First Aid 2014 page 599 | |||
|RightAnswer=B | |RightAnswer=B | ||
|WBRKeyword=Lung, Vasculature, Pulmonary hypertension, Hemodynamics, Hemodynamic, | |WBRKeyword=Lung, Vasculature, Pulmonary hypertension, Hemodynamics, Hemodynamic, | ||
|Approved=Yes | |Approved=Yes | ||
}} | }} |
Revision as of 23:48, 19 October 2014
Author | PageAuthor::William J Gibson |
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Exam Type | ExamType::USMLE Step 1 |
Main Category | MainCategory::Physiology |
Sub Category | SubCategory::Pulmonology |
Prompt | [[Prompt::An attending in the cardiac intensive care unit at major academic medical center is teaching a resident about the pulmonary vasculature. A patient with a history of hypertrophic cardiomyopathy is recovering from an anterior myocardial infarction and the following values are measured.
Pulmonary artery pressure (mean): 15 Pulmonary capillary wedge pressure (mean): 10 Aortic systolic pressure: 140 Aortic diastolic pressure: 90 Heart rate: 90 per minute Stroke Volume: 40 mL Which of the following corresponds to the pulmonary vascular resistance in this patient?]] |
Answer A | AnswerA::0.72 mmHg·min/L |
Answer A Explanation | AnswerAExp::Incorrect: See calculation in the explanation |
Answer B | AnswerB::1.39 mmHg·min/L |
Answer B Explanation | AnswerBExp::Correct: See calculation in the explanation |
Answer C | AnswerC::11.25 mmHg·min/L |
Answer C Explanation | AnswerCExp::Incorrect: See calculation in the explanation |
Answer D | AnswerD::13.9 mmHg·min/L |
Answer D Explanation | AnswerDExp::Incorrect: This result can be achieved by dividing the difference in systolic and diastolic aortic pressures and dividing by the cardiac output (3.6L/min) |
Answer E | AnswerE::20.83 mmHg·min/L |
Answer E Explanation | AnswerEExp::Incorrect: See calculation in the explanation |
Right Answer | RightAnswer::B |
Explanation | [[Explanation::In this question we are asked to calculate the pulmonary vascular resistance for this patient. Recall that the resistance of a vessel can be calculated by the change in pressure across the segment divided by the flow (R=P/Q). Generally, the pulmonary capillary wedge pressure is a good estimate of the pressure in the left atrium. Therefore, pulmonary vascular resistance is given by the formula:
<math>PVR = (P_{pulmonary artery} - P_{capillary wedge})/Cardiac Output</math> α Plugging in values from the above case we get the following: (15 mmHg - 10 mmHg)/(90 beats/minute*(.040 L/min))=5/3.60=1.39 mmHg·min/L.
References: |
Approved | Approved::Yes |
Keyword | WBRKeyword::Lung, WBRKeyword::Vasculature, WBRKeyword::Pulmonary hypertension, WBRKeyword::Hemodynamics, WBRKeyword::Hemodynamic |
Linked Question | Linked:: |
Order in Linked Questions | LinkedOrder:: |