WBR0025

Revision as of 00:09, 6 August 2013 by Gerald Chi (talk | contribs) (Gerald Chi moved page WBR114 to WBR0025 without leaving a redirect)
Jump to navigation Jump to search
 
Author PageAuthor::Raviteja Reddy Guddeti MBBS, Aarti Narayan MBBS
Exam Type ExamType::USMLE Step 2 CK
Main Category MainCategory::Internal medicine
Sub Category SubCategory::Cardiovascular
Prompt [[Prompt::A 65 year old male presents with fever, weakness, and chest pain that is pleuritic in nature. The pain is relieved by sitting up and leaning forward. The patient describes the pain as sharp and brief. Auscultation reveals friction rub. What is the pathognomonic EKG finding in this patient?]]
Answer A AnswerA::Universal ST segment elevation
Answer A Explanation AnswerAExp::Although universal ST segment elevation is commonly seen in acute pericarditis, it is not a pathognomonic finding.
Answer B AnswerB::T wave inversion and poor R wave progression.
Answer B Explanation AnswerBExp::T wave inversion and poor R wave progression suggests ischemia, and is not pathognomonic for acute pericarditis.
Answer C AnswerC::PR depression
Answer C Explanation AnswerCExp::PR depression is the correct answer.
Answer D AnswerD::Presence of a Q wave
Answer D Explanation AnswerDExp::Presence of a Q wave suggests an old infarct, and is not pathognomonic for acute pericarditis.
Answer E AnswerE::Poor R-wave progression
Answer E Explanation AnswerEExp::Poor R-wave progression can imply an old anterior MI, and is not pathognomonic for acute pericarditis.
Right Answer RightAnswer::C
Explanation [[Explanation::The correct answer is PR depression, as the patient has acute pericarditis. PR depression is an EKG finding which is pathognomonic in acute pericarditis, even though ST elevation is often seen in all leads universally. ST segment elevation is seen in other cardiac conditions such as STEMI, pulmonary embolism, therefore this finding is not pathognomonic.

Educational Objective:
References: ]]

Approved Approved::Yes
Keyword
Linked Question Linked::
Order in Linked Questions LinkedOrder::