WBR234
| Author | [[PageAuthor::Rim Halaby, M.D. [1]]] |
|---|---|
| Exam Type | ExamType::USMLE Step 1 |
| Main Category | MainCategory::Physiology |
| Sub Category | SubCategory::Renal |
| Prompt | [[Prompt::An experiment to measure the filtration fraction in healthy volunteers is conducted. One sample of the available urine and serum values is shown below. If the urine flow is 2.0 ml/min, what is the best approximate filtration fraction?
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| Answer A | AnswerA::20% |
| Answer A Explanation | AnswerAExp::According to the calculation, this is an incorrect answer. |
| Answer B | AnswerB::30% |
| Answer B Explanation | AnswerBExp::According to the calculation, this is an incorrect answer. |
| Answer C | AnswerC::35% |
| Answer C Explanation | AnswerCExp::According to the calculation, this is an incorrect answer. |
| Answer D | AnswerD::40% |
| Answer D Explanation | AnswerDExp::According to the calculation, this is a correct answer. |
| Answer E | AnswerE::45% |
| Answer E Explanation | AnswerEExp::According to the calculation, this is an incorrect answer. |
| Right Answer | RightAnswer::D |
| Explanation | [[Explanation::Despite the presence of several parameters, utilization of only creatinine and PAH is required to calculate the filtration fraction.
Filtration fraction (FF) is calculated by the following equation: FF (%) = (GFR / RPF) x 100 GFR = (UCr x V)/PCr = (100 x 2)/1 = 200 RPF = (UPAH x V)/PPAH = (50 x 2)/0.2 = 500 FF (%) = (GFR / RPF) x 100 = (200/500) x 100 = 0.4 x 100 = 40%
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| Approved | Approved::No |
| Keyword | |
| Linked Question | Linked:: |
| Order in Linked Questions | LinkedOrder:: |